SOLUTION: Find three consecutive odd integers such that three times the first minus the second is one more than the third.

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Question 46937: Find three consecutive odd integers such that three times the first minus the second is one more than the third.
Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive odd integers such that three times the first minus the second is one more than the third.
1st odd number: 2x+1
2nd odd number: 2x+3
3rd odd number: 2x+5
EQUATION:
3(2x+1)-(2x+3)-1=2x+5
6x+3-2x-3-1=2x+5
2x=6
x=3
2x+1=7 (1st odd)
2x+3=9 (2nd odd)
2x+5=11(3rd odd)
Cheers,
Stan H.