SOLUTION: Find 4 consecutive odd integers where the product of the two smaller numbers less than the product of the two larger numbers.

Question 465603: Find 4 consecutive odd integers where the product of the two smaller numbers less than the product of the two larger numbers.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find 4 consecutive odd integers where the product of the two smaller numbers less than the product of the two larger numbers.
:
4 consecutive odd integers, x, (x+2), (x+4), (x+6)
:
where the product of the two smaller numbers less than the product of the two larger numbers.
x(x+2) < (x+4)(x+6)
FOIL
x^2 + 2x < x^2 + 6x + 4x + 24
x^2 + 2x < x^2 + 10x + 24
x^2 - x^2 + 2x - 10x < 24
-8x < 24
x has to be positive, multiply both sides by -1, this reverses the inequality sign
8x > -24
x >
x > -3
An odd number greater than -3, is -1,
then the 4 odd integers: -1, +1, +3, +5
:
See if this satisfies the statement:
-1(+1) < 3 * 5
-1 < 15 is true enough
:
We can any odd x greater than -3 will satisfy the statement
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