SOLUTION: two consecutive numbers are squared and then added to gether to get the result of 113. What is the starting formula?
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Question 451604: two consecutive numbers are squared and then added to gether to get the result of 113. What is the starting formula?
Found 3 solutions by nerdybill, Alan3354, pedjajov:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
two consecutive numbers are squared and then added to gether to get the result of 113. What is the starting formula?
.
Let x = first consecutive number
then
x+1 = second consecutive number
.
x^2 + (x+1)^2 = 113 (you can probably leave it like this)
x^2 + (x+1)(x+1) = 113
x^2 + (x^2+x+x+1) = 113
x^2 + (x^2+2x+1) = 113
2x^2+2x+1 = 113
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Answer by pedjajov(51) (Show Source): You can put this solution on YOUR website!
Two consecutive numbers are x and x+1 so if their sum is 113 it is
Solutions for x in this quadratic equation are given as
It gives us x = 7 or x = -8
So numbers are 7 and 8, or -8 and -7.
Check1: , OK
Check2: , OK
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