SOLUTION: Find 3 consecutive multiples of 4 such that twice the sum of the last two numbers decreased by the second number is 4 less than 5 times the first number?

SOLUTION: Find 3 consecutive multiples of 4 such that twice the sum of the last two numbers decreased by the second number is 4 less than 5 times the first number?

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Question 449597: Find 3 consecutive multiples of 4 such that twice the sum of the last two numbers decreased by the second number is 4 less than 5 times the first number?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let the multiples be 4x, 4(x+1) and 4(x+2)
2(4(x+1)+(4(x+2))-4(x+1)=5*4x-4
2(4x+4+4x+8)-4x-4=20x-4
8x+8+8x+16-4x-4=20x-4
12x+20=20x-4
8x=24
x=3
.
12,16 and 20 are the 3 multiples of 4.
.
Ed
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