SOLUTION: find the sum of the first 500 counting numbers
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Question 447576: find the sum of the first 500 counting numbers
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
500 + 1 = 501
499 + 2 = 501
498 + 3 = 501
. . .
251 + 250 = 501
And there are 500/2 = 250 such pairs.
In general, the sum of consecutive positive integers is given by:
\ =\ \frac{(a\,+\,l)(l\,-\,a\,+\,1)}{2})
So for your problem:
\ =\ \frac{(1\,+\,500)(500\,-\,1\,+\,1)}{2}\ =\ 501\ \times\ 250)
Super Double Plus Extra Credit:
What is the sum of the even integers between 200 and 300 inclusive?
John
My calculator said it, I believe it, that settles it
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