SOLUTION: when one integer is added to the square of the next consecutive integer, the sum is 71.Find the two integers.

SOLUTION: when one integer is added to the square of the next consecutive integer, the sum is 71.Find the two integers.

Algebra.Com

Question 437167: when one integer is added to the square of the next consecutive integer, the sum is 71.Find the two integers.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
x+(x+1)2=71
x+x2+2x+1=71
x2+3x-70=0
(x+10)(x-7)=0
x=-10,7
Ignoring the negative result, we get the first integer to be 7, the second to be 8.
RELATED QUESTIONS
When one integer is added to the square of the next consecutive integer, the sum is 41.... (answered by oberobic)

if one half of an integer is added to one fifth the next consecutive integer, the sum is... (answered by ewatrrr)

if one half of an integer is added to one fifth the next consecutive integers,the sum is... (answered by bucky)

1.if one-third of an integer is added to one-half of the next consecutive integer, the... (answered by stanbon,rchill)

If 1/3 of an integer is added to 1/4 of the next consecutive integer the sum is 23. Find (answered by asuar010)

The product of two consecutive integers is 71 more than the square of the preceding... (answered by ramkikk66)

The square root of the sum of two consecutive integer is 7. Find the two integers (answered by Fombitz,Alan3354)

if 1/3 of an integer is added to 1/4 of the next consecutive integers the sum is 23. find (answered by ikdeep)

the square root of the sum of two consecutive integers is eleven. find the larger... (answered by suan,drk)