SOLUTION: two integers have a product of 32. one integer is twice the other. what are the integers

Question 428267: two integers have a product of 32. one integer is twice the other. what are the integers
Found 2 solutions by Gogonati, John10:
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Solution: Let x the first integer, then the second is 2x, and their product is:

x=+/-sqrt(16)
x=4 and x=-4
Answer: the integers are, 4 and 8 or -4 and -8. We have two solutions.
Done.
Answer by John10(297) (Show Source): You can put this solution on YOUR website!
two integers have a product of 32. one integer is twice the other. what are the integers
Let x and y are two integer
The product is 32: x*y = 32 (1)
One integer is twice the other: y = 2x (2)
Substitute (2) into (1) to find x:
x(2x)= 32
2x^2 = 32
x^2 = 32/2 = 16
x = 4 or x = -4
If x = 4 then y = 2(4) = 8
If x = -4 then y = 2(-4) = -8
So there are two pairs (4 and 8) and (-4 and -8)
Have a great one! John10
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