SOLUTION: the second of two numbers is two more than three times the first number. Their sum is negative twenty-two

Question 426311: the second of two numbers is two more than three times the first number. Their sum is negative twenty-two
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"the second of two numbers is two more than three times the first number. Their sum is negative twenty-two"

x = first number
3x + 2 = second number {2nd is two more than three times first}

x + 3x + 2 = -22 {sum is negative twenty-two}
4x + 2 = -22 {combined like terms}
4x = -24 {subtracted 2 from both sides}
x = -6 {divided both sides by 4}
3x + 2 = -16 {substituted -6, in for x, into 3x + 2}

-6 and -16 are the two numbers
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