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Question 423814: The sum of two digits of a number is 11.
If the digits are reversed the number is 63 more than the original number.
What is the original number?
Answer by rfadrogane(214)   (Show Source):
You can put this solution on YOUR website! The sum of two digits of a number is 11.
If the digits are reversed the number is 63 more than the original number.
What is the original number?
Let: N = the original number.
N = 10t+u
t=the ten's digit
u-unit digit
Sol'n:
t+u=11 ----(1), the sum of two digits of a number is 11.
10u+t=(10t+u)+63, when the digits are reversed the number is 63 more than the original number.
9t-9u=-63, when divide by 9
t-u = -7----(2)
Add (1) and (2).
2t=4
t=2 and for u:
u=11-2
u=9
thus,
N=10(2)+9
N=29 ----answer
Check:
92-29=63
^_^
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