SOLUTION: Suppose 2001 is divided by an integer n. For which integers n is the remainder 9?
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Question 420129: Suppose 2001 is divided by an integer n. For which integers n is the remainder 9?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
We have , or , where q is a positive integral quotient. Now 1992 = . We want n to be relatively prime to 9, AND greater than 9. From the prime factorization of 1992, the only possible values of n are 83 (a prime number), 2*83 = 166, , .
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