SOLUTION: Find two consecutive even intergers such that the smaller added to three times the larger give a sum of 46.

Question 420074: Find two consecutive even intergers such that the smaller added to three times the larger give a sum of 46.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"Find two consecutive even intergers such that the smaller added to three times the larger give a sum of 46."

x = 1st consecutive even integer
x + 2 = 2nd consecutive even integer

x + 3(x + 2) = 46 {smaller added to 3 times larger, is 46}
x + 3x + 6 = 46 {used distributive property}
4x + 6 = 46 {combined like terms}
4x = 40 {subtracted 6 from both sides}
x = 10 {divided both sides by 4}
x + 2 = 12 {substituted 10, in for x, into x + 2}

10 and 12 are the two consecutive even integers
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