Hi
one integer is 5 less than 2 times another
Let x and (2x-5) represent the integers
Question states***
x(2x-5)=12
2x^2-5x-12 = 0
factoring
(2x+3)(x-4)=0 |Note:SUM of the inner product(3x) and the outer product(-8x) = -5x
(2x+3) = 0 Tossing out fractional answer
(x-4)=0 x = 4 the Integers are 4 and 3
CHECKING our Answer***
3*4 = 12