SOLUTION: The sum of the squares of two consecutive even integers is 580. What are the integers?
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Question 417842: The sum of the squares of two consecutive even integers is 580. What are the integers?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The sum of the squares of two consecutive even integers is 580.
What are the integers?
:
x^2 + (x+2)^2 = 580
x^2 + x^2 + 4x +4 = 580
2x^2 + 4x + 4 - 580 = 0
2x^2 + 4x -576
Simplify, divide by 2
x^2 + 2x - 288 = 0
Factors to
(x+18)(x-16) = 0
The positive solution
x = 16 and 18 are the integers
:
:
Check on calc: 16^2 + 18^2 = 580
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