SOLUTION: divide 224 into two parts such that when the larger part is divided by the smaller part, the quotient is 2 and the remainder is half of the smaller part. find the larger part.

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Question 417383: divide 224 into two parts such that when the larger part is divided by the smaller part, the quotient is 2 and the remainder is half of the smaller part. find the larger part.
Found 2 solutions by ewatrrr, htmentor:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
divide 224 into two parts
Let x and (224-x) represent the smaller and larger part respectively
Question states***

Solving for x
2(224-x) = 4x + x^2 |Multiplying thru by 2x
x^2 +6x -448 = 0



x = 18.3776 | Tossing out negative solution
CHECKING our Answer***
205.6224/18.3776 = 11.1888 = 2 + (1/2)18.3776 = 2 + 9.1888

Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
Let the two numbers be x and y
Then we have (1)
This step is a little tricky. We are told the quotient is 2 and the remainder is half the denominator (the smaller number). The expression can be written
(2).
This might be hard to follow, so let's use an example: Separating the terms, we have .
This says that the quotient is 2 with a remainder of 3, which is half the denominator (the smaller part).
Solving for x in (2) gives or .
Substituting into (1) gives or -> .
Therefore .
So the smaller part is 64 and the larger part is 160.
Check: 160/64 = 2, with a remainder of 160-2*64 = 160-128=32, which is half of 64.

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