Hi

Let x, (2x+10) and (x + 2 x + 10 -10) represent the three numbers

Question states***

 x + (2x+10) +(3x) = 100

Solving for x

     6x =  90

      x = 15         | Numbers are:  15, 40, 45

CHECKING our Answer***

  15 + 40 + 45 = 100 

Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
 x+y+z=100 (1)

y=2x+10 (2) 2nd number (y) is (=) 10 more (+) than twice (x) the 1st

z=x+y-10 (3) 3rd number (z) is 10 less (-) than sum of first two (x+y)

Solve for x+y in (3) -> x+y=z+10 

Insert into (1) -> (z+10)+z=100 -> 2z+10=100 -> z=45

From (1) x+y=100-z -> x+y=55 -> y=55-x

Subtitute into (2) -> 55-x=2x+10 -> 3x=45 -> x=15

Since x+y+z=100 -> 15+y+45=100 -> y=40

Ans: x=15,y=40,z=45



 

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