SOLUTION: how to find two cosecutive even integers whose product is 168?

Question 415126: how to find two cosecutive even integers whose product is 168?

Found 2 solutions by sudhanshu_kmr, mananth:
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

Let integers are x and x+2
x(x+2) = 168
=> x^2 +2x -168 = 0
=> x^2 +14x -12x -168 = 0
=> x(x +14) -12(X+ 14) = 0
=> (x-12)(x+14) = 0

so, x = 12
numbers are 12 and 14

Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
x(x+2)=168
x^2+2x-168=0
x^2+14x-12x-168=0
x(x+14)-12(x+14)=0
(x-12)(x+14)=0
x= 12 OR -14
12 , 14
-14,-12
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