Hi

2 consecutive 2-digit numbers

Let x and (x+1) represent the numbers

Question states***

  x(x+1) = 812

Solving for x

 x^2 + x - 812 = 0

factoring

(x+29)(x-28)= 0

(x+29)= 0  x = -29     The 2 consecutive 2-digit numbers are -29,-28

(x-28)= 0  x = 28      The 2 consecutive 2-digit numbers are 28,29 

Answer by emargo19(101)   (Show Source): You can put this solution on YOUR website!
 Let 1st number=x

2nd number=x+1







Lets use the quadratic equation to factor the equation 



 a=1 b=1 c=-812





 

  

  

  

The first number is -28 and second number is 29 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 

--> 28 & 29

 

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