SOLUTION: In how many ways can a committee of 3 be selected from a group of 5?

Question 4083: In how many ways can a committee of 3 be selected from a group of 5?
Found 2 solutions by rapaljer, CharStar:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
This is a combination problem, since the order of selection is not significant. Standard notation for this can be written C(5,3), and most standard calculators can be used to do the calculation without even understanding it.

However, understanding it, you can calculate the product of three numbers beginning at 5 and counting down: 5 times 4 times 3, and then divide by the product of the three numbers beginning at 3 and counting down: 3 times 2 times 1.

Final answer is (5*4*3) over (3*2*1) or 60/6 = 10.
Answer by CharStar(110) (Show Source): You can put this solution on YOUR website!
Since n=5 and r=3 (five people taken three at a time), then the equation is as follows
Use the following formula for combinations nCx=(n,x)=n!/x!(n-x)
Looks confusion doesn't it.
n=5
x=3

Now solve
5 x 4 x 3 x 2 x 1
_________________
3 x 2 x 1 x 2 x 1
You can cross out or multiply and divide.
120/12 = 10

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