SOLUTION: Find three consecutive positive odd integers such that the square of the smallest exceeds twice the largest by 91. Thank you so much!

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Find three consecutive positive odd integers such that the square of the smallest exceeds twice the largest by 91. Thank you so much!      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 406792: Find three consecutive positive odd integers such that the square of the smallest exceeds twice the largest by 91.
Thank you so much!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
x , x+2 , and x+4 are the integers

x^2 - 91 = 2(x + 4) ___ x^2 - 91 = 2x + 8

x^2 - 2x - 99 = 0

factoring ___ (x - 11)(x + 9) = 0