SOLUTION: Find two consecutive odd integers such that six times the first equals ten more than four times the second.

Question 404407: Find two consecutive odd integers such that six times the first equals ten more than four times the second.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find two consecutive odd integers such that six times the first equals ten more than four times the second.
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1st odd: 2x-1
2nd odd: 2x+1
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Equation:
6(2x-1) = 4(2x+1)+ 10
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12x - 6 = 8x + 4 + 10
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4x = 20
x = 5
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1st odd: 2*5-1 = 9
2nd odd: 2*5+1 = 11
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Cheers,
Stan H.
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