SOLUTION: The product of two consecutive positive intergers is 5 more than their sum. Find the integers. Please help me solve this. Debra

Question 398659: The product of two consecutive positive intergers is 5 more than their sum. Find the integers. Please help me solve this. Debra
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x*(x+1) = x + x+1 + 5

(x-3)(x+2) = 0
x = -2, 3
--> -2 & -1 or 3 & 4

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive positive integers is 5 more than their sum. Find the integers.
---
1st: x
2nd: x+1
-----
Equation:
x(x+1) = (x + (x+1) + 5)
----
x^2+x = 2x+6
x^2-x-6 = 0
------
Factor:
(x-3)(x+2) = 0
Positive solution:
x = 3
=====
1st = x = 3
2nd = x+1 = 4
--------------------
Cheers,
Stan H.
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