SOLUTION: find three consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen.

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Question 397512: find three consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen.
Found 2 solutions by scott8148, ewatrrr:
Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
n , n+2 , n+4

2(n + n+4) = n+2 + 15

4n + 8 = n + 17 ___ 3n = 9
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states*** 

 2[x + (x+4)] = (x+2) + 15

solving for s

   4x + 8 = x + 17

     3x = 9

      x = 3   The three consecutive odd integers are 3,5,7



CHECKING our Answer***

 2(3+7) = 20 = 5 + 15 

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