SOLUTION: I still need help getting the three numbers. Thanks The sum of three numbers is 116. The third number is 3 times the second. The second number is 9 more than the first . What a

Question 395049: I still need help getting the three numbers. Thanks
The sum of three numbers is 116. The third number is 3 times the second. The second number is 9 more than the first . What are the numbers?
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x + y + z = 116
z = 3y
y = x+9
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Substitute for z and for y and solve for z.

Answer by valnadam(5) (Show Source): You can put this solution on YOUR website!
I think I figured it out
First number is 16
Second number is 25
Third number is 75
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