Hi

Let x,(x+2),(x+4) represent the three consecutive odd integers 

Questions States***

x +(x+2) +(x+4) = 63

Solving for x

   3x + 6 = 63

       3x = 57

        x = 19  the three consecutive odd integers are 19,21,23



CHECKING our Answer

19 +21 + 23 = 63

 

Answer by spikendb(5)   (Show Source): You can put this solution on YOUR website!
 Three consecutive odd integers that equal 63.



Since 1, 3, 5... each number has to add 2 to itself to equal the next.

1 plus 2 equals 3 and so on.



So the three unknown, consecutive odd numbers algebraically would be set up as:



Since all the numbers are being added, you can drop the parentheses.



You, then, combine like terms.

There are 3 x's, and a 4 and a 2.

So you have:

3x+6 = 63

You subtract 6 from both sides of the equation.

3x = 57

Then you divide both sides of the equation by 3.

x = 19.

Since x is 19, you plug that in the original formula we created.

19+(19+2)+(19+4) = 63

You solve the problem.

19+21+23 = 63

63 = 63.

So your answer is:

The three consecutive odd integers that equal 63 are 19, 21, and 23. 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 63/3 = 21, the middle number

--> 19, 21 & 23

 

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