Hi,         

Let x,(x+1),(x+2) represent the three consecutive integers

question states****

 x(x+2) = 440

x^2 + 2x - 440 = 0

factoring

(x+22)(x-20)= 0 Note:SUM of the inner product(22x) and the outer product(-20x) = 2x

(x+22)= 0

   x = -22  three consecutive integers -22,-21,-20

or

(x-20)= 0 

    x = 20 three consecutive integers 20,21,22



CHECKING our Answer

-22*-30 = 440

10*22 = 440 

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