SOLUTION: Hi! Can you help me with this problem?
One number is 4 times another number. The larger number is also 87 more than the smaller number. Find the numbers.
If you could help me it
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Question 38961: Hi! Can you help me with this problem?
One number is 4 times another number. The larger number is also 87 more than the smaller number. Find the numbers.
If you could help me it would be very much appreciated.
Thanks.
Found 2 solutions by fractalier, stanbon:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let x be the smaller and y be the larger.
so we have
y = 4x and
y - x = 87
Now substituting we have
4x - x = 87
3x = 87
x = 29
y = 4x = 116
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One number is 4 times another number. The larger number is also 87 more than the smaller number. Find the numbers.
Let "s" be the smaller and "l" be the larger number.
EQUATIONS:
l=4s
s=l-87
Substitute to get:
s=4s-87
-3s=-87
s=29
l=29+87=116
Cheers,
Stan H.
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