Hi,         

three positive integers are (x-1),x and (x+1) 

Write as we Read***

 x(x-1)(x+1) = 40[(x-1)+ x +(x+1)]

 x(x-1)(x+1) = 40[3x]

  (x-1)(x+1) = 120

Solving for x

   x^2 - 1 = 120

     x^2 = 121

     x = 11 (tossing out negative solution) Positive integers are 10,11,12



CHECKING our Answer***

  1320 = 40* 33 

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