SOLUTION: Find both consecutive even integers if their product is 10 less than 9 times the second integer

Question 386977: Find both consecutive even integers if their product is 10 less than 9 times the second integer
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find both consecutive even integers if their product is 10 less than 9 times the second integer
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1st: 2x
2nd: 2x+2
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Equation:
(2x(2x+2)) = 9(2x+2)-10
4x^2+4x = 18x+8
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4x^2-14x-8 = 0
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2x^2-7x-4 = 0
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2x^2-8x+x-4 = 0
2x(x-4)+(x-4) = 0
(x-4)(2x+1) = 0
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x = 4 or x = -1/2
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Two solutions:
If x = 4:
2x = 8
2x+2 = 10
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If x = (-1/2)
2x = -1
2x+2 = +1
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Only real solution:
1st: 2x = 8
2nd: 2x+2 = 10
=======================
Cheers,
Stan H.
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