SOLUTION: One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers
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Question 383213: One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
n = 2m + 8
(n + m) - 9 = 14
=================
2m + 8 + m - 9 = 14
3m - 1 = 14
3m = 14 + 1
3m = 15
m = 15/3
m = 5
n = 2(5) + 8
n = 10 + 8
n = 18
The numbers are 5 and 18.
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