SOLUTION: eight times the sum of three consecutive even integers is 98 more than 23 times the smallest of the three integers. what are the integers?

Question 381365: eight times the sum of three consecutive even integers is 98 more than 23 times the smallest of the three integers. what are the integers?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the integers be n,n+2,n+4
...
8times the sum
8*(n+n+2+n+4)
8*(3n+6)
...
23 times smallest = 23n
add 98
23n+98
...
8(3n+6)=23n+98
24n+48=23n+98
-23n -23n
24n-23n+48=23n-23n+98
n+48=98
-48 -48
n+48-48=98-48
n=50
...
the numbers are 50, 52,54
..
m.ananth@hotmail.ca
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