SOLUTION: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third. This is what I have: 20(x + 2(x+2))=

SOLUTION: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third. This is what I have: 20(x + 2(x+2))=

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Question 372497: Using algebra, find three consecutive odd integers, such that the sum of the smallest and twice the second is twenty more than the third.
This is what I have:
20(x + 2(x+2))= x+6
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
, and are the integers.
.
.
.

Now solve for .

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