SOLUTION: Three times one number minus a second is 8, and the sum of the numbers is 12. Find the numbers.

Algebra.Com
Question 369177: Three times one number minus a second is 8, and the sum of the numbers is 12. Find the numbers.
Answer by lefty4ever26(59)   (Show Source): You can put this solution on YOUR website!
3 times one number (3x) minus a second (-y) is 8 (=8). SO 3x-y=8.
sum of numbers (x+y) is 12 (=12). SO x+y=12.

Solve this equation for y to get Then you will plug this new value of y into the first equation and solve for x.




Then plug this value for x back into one of the equations to find y.



So the two numbers are 5 and 7.

RELATED QUESTIONS

Three times one number minus a second is 8, and the sum of the number is 12. Find the... (answered by chana)
Three time a number minus a second is 8. The sum of the numbers is 12. Find the... (answered by solver91311)
The sum of three times the number and a second number is one. The difference of the first (answered by lwsshak3)
can you please help me with this problem? three times one number minus a second number is (answered by stanbon)
Twice one number minus three times a second is equal to 2 and the sum of these numbers is (answered by mananth)
One number is three times a second number, and twice the sum of the numbers is 168. Find... (answered by mananth)
The sum of three numbers is 10. Two times the second number minus the first number is... (answered by lwsshak3)
Three times a first number minus the second number is 20. The sum of the two numbers is... (answered by jim_thompson5910)
Three times one number plus a second number is 40,and the one number minus the second... (answered by macston)