SOLUTION: Consecutive problem: Two times the first of three consecutive even integers less three times the second equals 4. Form an equation and solve it to find the three numbers. Th

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Question 367645: Consecutive problem:
Two times the first of three consecutive even integers less three times the second equals 4. Form an equation and solve it to find the three numbers.
This what I have:
2x+x+x+1-3=4
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(13828) (Show Source):
You can put this solution on YOUR website!
, , and would be three consecutive even integers.

Now solve for .

Answer by ewatrrr(10682) (Show Source):
You can put this solution on YOUR website!

Hi,
Yes! Letting x represent the first of the three consecutive even integers.
***consecutive even integers differ by 2.
the three consecutive even integers would be x, (x+2) and (x+4)
Write as we Read***
2x - 3(x+2)= 4
solve for x
-x - 6 = 4
-10 = x
-10,-8 and -6 would be the three consecutive even integers
checking our answer
-20 - 3*-8 = -20 + 24 = 4