SOLUTION: if n>0 and 9x^2+kx+36=(3x+n)^2 for all x, what is k-n?

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Question 366632: if n>0 and 9x^2+kx+36=(3x+n)^2 for all x, what is k-n?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

+9x%5E2%2Bkx%2B36=%283x%2Bn%29%5E2+
+9x%5E2%2Bkx%2B36=9x%5E2%2B6nx%2Bn%5E2
Compare terms,
n%5E2=36
n=0+%2B-+6
.
.
.
kx=6nx
k=6n
k-n=6n-n
k-n=5n
highlight%28k-n=0+%2B-+30%29