SOLUTION: two numbers differ by 8. The sum of twice the smaller and the larger is the same as twice the larger increased by 4.
I am a 10th grade student. I have tried different numbers. I
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Question 365380: two numbers differ by 8. The sum of twice the smaller and the larger is the same as twice the larger increased by 4.
I am a 10th grade student. I have tried different numbers. I tried this but I can not figure out why I can not find the second number that should be 8 less than the larger number
I made up numbers to figure out how to come up with x and y. But I think I am missing one whole step where (x-8) should be.
x= one number and the other number is x-8
My formula that I tried is
2x + x-8) + 4= 90
2x+x-8+4=90
3x-4=90-4
3x=86
and then we got confused
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
two numbers differ by 8. The sum of twice the smaller and the larger is the same as twice the larger increased by 4.
x = smaller
y = x + 8 (larger)
2x + y = 2y + 4
2x = y + 4
2x = x+8 + 4 = x + 12
x = 12
--> 12 & 20
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I am a 10th grade student. I have tried different numbers. I tried this but I can not figure out why I can not find the second number that should be 8 less than the larger number
I made up numbers to figure out how to come up with x and y. But I think I am missing one whole step where (x-8) should be.
x= one number and the other number is x-8
My formula that I tried is
2x + x-8) + 4= 90
2x+x-8+4=90
3x-4=90-4
3x=86
and then we got confused
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