# SOLUTION: the perimeter around a rectangle is 48 inches. the length of the rectangel is 2 inches more thatn the width. what is the width of the rectangel?

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 Question 362743: the perimeter around a rectangle is 48 inches. the length of the rectangel is 2 inches more thatn the width. what is the width of the rectangel?Found 2 solutions by Manny Pacquiao, Jstrasner:Answer by Manny Pacquiao(82)   (Show Source): You can put this solution on YOUR website!2+2=4 22+22=44 +4=48 looks like 2 and 22 is your rectangle.. must be a weird looking rectangle..are you sure this is right? Answer by Jstrasner(106)   (Show Source): You can put this solution on YOUR website!Hey, So for this one there are 2 equations that we have: 2L + 2w = 48 L = 2 + w So all we need to do is substitute 2 + w for L in the first equation: 2(w+2) + 2w = 48 => 2w + 4 + 2w = 48 => 4w = 44 => w=11 Therefore: L = 2 + 11 => 13 Therefore: W= 11, L=13 I hope this helps!