SOLUTION: Solve, show work. The larger of two consecutive integers is 4 less than the other. What are the two numbers?

SOLUTION: Solve, show work. The larger of two consecutive integers is 4 less than the other. What are the two numbers?

Algebra.Com

Question 362732: Solve, show work.
The larger of two consecutive integers is 4 less than the other. What are the two numbers?
Answer by Manny Pacquiao(82) (Show Source): You can put this solution on YOUR website!
That doesn't make any sense. There is no number that is 4 less and larger at the same time.
RELATED QUESTIONS
how do you solve this equation. 3 times the smaller of 2 consecutive even integers is 4... (answered by mananth)

THE SUM OF TWO EVEN CONSECUTIVE INTEGERS IS 52 LESS THAN THE LARGER INTEGER. WHAT ARE THE (answered by nyc_function)

Find 4 consecutive even integers where the product of the two smaller numbers is 72 less... (answered by RAY100)

Find 4 consecutive even integers where the product of the two smaller numbers is 56 less... (answered by Theo)

Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less... (answered by josmiceli)

Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less... (answered by stanbon)

Find 4 consecutive even integers where the product of two smaller numbers is 56 less than (answered by josmiceli)

two positive numbers are consecutive odd integers. the square of the smaller is 10 less... (answered by stanbon)

The product of two consecutive integers is 16 less than the square of the next larger... (answered by ewatrrr)