SOLUTION: The sum of 5 and a negative integer is greater than -4 and less than 0. How many possible negative intergers satisfy the information?

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Question 36086This question is from textbook Working with Numbers Algebra
: The sum of 5 and a negative integer is greater than -4 and less than 0. How many possible negative intergers satisfy the information?This question is from textbook Working with Numbers Algebra

Answer by jcmtnez(53) (Show Source):
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-4<5+x<0 and x<0 Because it is negative
-4=5+x
-9=x Therefore x must be greater than -9
5+x=0
x=-5 Therefore x must be less than -5
The solution of the problem is the open interval of the numbers greater than -9 and less than -5, S=(-6,-7,-8) Are the threes negative integers that are solution to the problem.