SOLUTION: Find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 70?

Algebra.Com
Question 360166: Find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 70?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
*Note: consecutive odd integers differ by 2
Le x represent the first odd integer.
Then (x+2) and(x+4) would be the next two consecutive odd integers
write as we read
x + 2(x+2) + 3(x+4) = 70
Solving for x
6x +4 + 12 = 70
6x = 54
x = 9
three consecutive odd integers are 9, 11, 13
checking our answer
9 + 22 + 39 = 70
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