SOLUTION: find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.

Question 360059: find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
Found 2 solutions by vleith, mananth:
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Let the smallest number be x.
Then the next two natural numbers are x+1 and x +2
You are told

So the numbers are 40, 41 a nd 42.
Check your answer, Is 40+41 = 42+39??
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
...
x,x+1,x+2
...
x+x+1=x+2+39
2x+1=x+41
2x-x=41-1
x=40
...
40,41,42
...
m.ananth@hotmail.ca
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