SOLUTION: A positive real number is bigger than its square root by 6. Find the number.

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Question 354176: A positive real number is bigger than its square root by 6. Find the number.
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
x=sqrtx+6
sqrtx=x-6 square both sides.
x=x^2-12x+36
x^2-12x-x+36=0
x^2-13x+36=0
(x-9)(x-4)=0
x-9=0
x=9 ans.
Proof:
9=sqrt9+6
9=3+6
9=9

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