SOLUTION: The larger of two consecutive integers is 11 more than one half the smaller

Question 353690: The larger of two consecutive integers is 11 more than one half the smaller
Found 2 solutions by checkley77, jsmallt9:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x & x+1 are the 2 integers.
x+1=(x+11)/2 cross multiply
2(x+1)=x+11
2x+2=x+11
2x-x=11-2
x=9 ans.
Proof:
9+1=(9+11)/2
10=20/2
10=10
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Let x = the larger integer.
Then x-1 would be the next smaller integer.
Now "The larger of two consecutive integers is 11 more than one half the smaller." translates into:

Simplifying we get:

Get rid of the fractions by multiplying both sides by 2:

Subtracting x from each side we get:

"x", as we said earlier, is the larger integer and "x-1" or 20 is the smaller integer. To check you can easily determine that the larger number, 21, is actually 11 more than half of the smaller, 20.
RELATED QUESTIONS
The larger of two consecutive integers is one more than twice the smaller. Find... (answered by richwmiller)
The larger of two consecutive integers is one more than twice the smaller. Find... (answered by Alan3354)
two consecutive integers with half of the smaller equual to 4 more than one third of the... (answered by mananth)
Half of the smaller of two consecutive even integers is equal to two more than the larger (answered by ankor@dixie-net.com)
The smaller of two consecutive even integers is five more than one half of the greater. (answered by josmiceli)
The smaller of two consecutive even integers is five more than one half of the greater. (answered by fractalier)
The smaller of two consecutive even integers is five more than one-half of the greater.... (answered by midwood_trail)
two times the smaller of two consecutive even integers is 18 more than the... (answered by CubeyThePenguin)
Two times the smaller of two consecutive even integers is 18 more than the... (answered by CubeyThePenguin)