SOLUTION: a wallet has $460 in $5, $10, and $20 Bills. The number of $5 bills exceeds twice the number of $10 bills by 4, while the number of $20 bills is 6 fewer than the number of $10 bill

Question 352147: a wallet has $460 in $5, $10, and $20 Bills. The number of $5 bills exceeds twice the number of $10 bills by 4, while the number of $20 bills is 6 fewer than the number of $10 bills. How many bills of each type are there?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET X= THE NUMBER OF $10 BILLS.
20(X-6)+10X+5(2X+4)=460
20X-120+10X+10X+20=460
40X=460+120-20
40X=560
X=560/40
X=14 NUMBER OF $10 BILLS.
14-6=8 NUMBER OF $20 BILLS.
2*14+4=28+4=32 $5 BILLS.
PROOF:
20*8+14*10+5*32=460
160+140+160=460
460=460

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