SOLUTION: find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times the third

SOLUTION: find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times the third

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Question 351359: find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times the third
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET 3 x+3 & X+6 BE THE 3 NUMBERS.
6X=4(X+6)+48
6X=4X+24+48
6X-4X=72
2X=72
X=72/2
X=36 ANS. FOR THE SMALLER NUMBER
36+6=42 ANS. FOR THE LARGER NUMBER.
PROOF:
6*36=4*42+48
216=168+48
216=216
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