SOLUTION: If you add the consecutive counting numbers starting with 1, what number will cause the sum to exceed 1000? Explain.

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Question 351050: If you add the consecutive counting numbers starting with 1, what number will cause the sum to exceed 1000? Explain.
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
n=number of terms. a[1]=1st term, a[n]=final term, S=sum of finite arithmetic sequence.
n/2(a[1]+a[n])=S[n]
n/2(1+n)>=1000
n(n+1)>=2000
n^2+n-2000>=0 Quadratic formula (below)
n>=44.22
n=45 the number that will cause the sum to exceed 1,000.
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Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=8001 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 44.2241545476267, -45.2241545476267. Here's your graph:

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