SOLUTION: Twice one number minus three times a second is equal to 2 and the sum of these numbers is 11. Find the numbers.
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Question 348571: Twice one number minus three times a second is equal to 2 and the sum of these numbers is 11. Find the numbers.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let numbers be x & y
3x-2y=2..................1
x+y=11...................2
..
Multiply equation 2 by 2
2x+2y=22
3x-2y+2x+2y=22+2
5x=24
x=24/5
plug the value of x in equation 1
you will get y =31/5
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