SOLUTION: Hello I really need some assistance with the following algebra word problem: "An Object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet

Question 348238: Hello I really need some assistance with the following algebra word problem:
"An Object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadractic equation h=16t^2 + 48t + 160. When will the object hit the ground?
Thank you for your assistance in advance
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You can use the equation to get clues for how to proceed
Like lots of motion problems, it starts at
What is at ?

This is saying that you are 160 ft above ground when you
throw the object up. There will be some value of
that will give me when the object is on it's way
down. This means it's back at your level on top of the building.
You want to find at which is

I can solve using quadratic formula

This makes no sense- the square root is of a negative
The equation should be
, then

(can't use this - negative number)

The object hits the ground in 5 sec
I can plot this as vs (note that is divided by here)

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