SOLUTION: The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable "w" for width).

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 Question 348019: The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable "w" for width). Found 2 solutions by nerdybill, solver91311:Answer by nerdybill(6959)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable "w" for width) . Area of any rectangle = width * length Perimeter of any rectangle = 2(width+length) . Let w = width and temporarily x = length . From the problem, perimeter is: 1.5wx . But, Perimeter = 2(w+x) So, then we have 1.5wx = 2(w+x) Solving for x: 1.5wx = 2(w+x) 1.5wx = 2w+2x 1.5wx-2x = 2w factoring the left: x(1.5w-2) = 2w x = 2w/(1.5w-2) . So, your answer would be length is equal to: 2w/(1.5w-2) Answer by solver91311(16885)   (Show Source): You can put this solution on YOUR website! The area of a rectangle is given by: and the Perimeter is given by: Where represents the measure of the length and represents the measure of the width. But we are given that So: John My calculator said it, I believe it, that settles it