SOLUTION: Twice a number decreased by three, and that difference divided by five more than the number.

Question 346117: Twice a number decreased by three, and that difference divided by five more than the number.
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Let n = the number
Twice a number decreased by three = 2n - 3.
...that difference divided by five more than the number = (2n - 3)/(n + 5).
The entire statement = (2n - 3)/(n + 5).
What exactly do you need done with this algebraic fraction?
In other words, where is the rest of the question?

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