SOLUTION: Find the difference between the sum of the first 600 multiple of 3 and the sum of the first 600 odd numbers
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Question 343592: Find the difference between the sum of the first 600 multiple of 3 and the sum of the first 600 odd numbers
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of a series of numbers is given by the first plus the last times the number of numbers divided by 2.
n}{2})
The first multiple of 3 is 3, the 600th multiple of 3 is 1800, and there are 600 numbers.
The first odd number is 1, the 600th odd number is 2 X 600 - 1 = 1199, and there are 600 numbers.
You want:
(600)}{2}\ -\ \frac{(1\ +\ 1199)(600)}{2}\ =\ (300)(1803\ -\ 1200)\ =\ 300\ \times\ 603)
John
My calculator said it, I believe it, that settles it
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